3x^(1/3)+2x^(2/3)=5

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Solution for 3x^(1/3)+2x^(2/3)=5 equation: 


x in (-oo:+oo)

2*x^(2/3)+3*x^(1/3) = 5 // - 5

2*x^(2/3)+3*x^(1/3)-5 = 0

t_1 = x^(1/3)

2*t_1^2+3*t_1^1-5 = 0

2*t_1^2+3*t_1-5 = 0

DELTA = 3^2-(-5*2*4)

DELTA = 49

DELTA > 0

t_1 = (49^(1/2)-3)/(2*2) or t_1 = (-49^(1/2)-3)/(2*2)

t_1 = 1 or t_1 = -5/2

t_1 = -5/2

x^(1/3)+5/2 = 0

1*x^(1/3) = -5/2 // : 1

x^(1/3) = -5/2

( -5/2 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 1

x^(1/3)-1 = 0

1*x^(1/3) = 1 // : 1

x^(1/3) = 1

x^(1/3) = 1 // ^ 3

x = 1

x = 1

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